It uses.replace(/[xy]/g, ...) to find every x or y in the string and replace it with a computed value. — Source: ChatGPT
const r = (Math.random() * 16) | 0;
This is a quick and clever way to generate a randomintegerbetween0 and 15 (inclusive). — Source: ChatGPT
const v = c === 'x' ? r : (r & 0x3) | 0x8;
If the character is'x':
v = r;
Just use the random valuer (between 0–15).
No constraints — we just need a hex digit
If the character is'y':
v = (r & 0x3) | 0x8;
This is bit-level wizardry to force they digit to follow the UUID variant rules, which say:
The first two bits of theycharacter should be10in binary.
So, here’s how the logic achieves that:
Step-by-step:
r & 0x3: keeps only the last 2 bits of r
→ this gives values between 0 and 3 (00, 01, 10, 11)
| 0x8: sets the first two bits to 10 (i.e., 1000 in binary → 8 in hex)
That guaranteesv will be one of:
8 (1000), 9 (1001), a (1010), or b (1011)
— Source: ChatGPT
I highlighted the answers from ChatGPT here in this article, but from what I understood, that “y” in the string exists for a reason and that reason is that UUID follows a guideline that expects “y” to follow a certain pattern.
Hey, my name is Ramu Narasinga. I study large open-source projects and create content about their codebase architecture and best practices, sharing it through articles, videos.